A) 1020
B) 105
C) 10
D) 1010
Correct Answer: A
Solution :
In a galvanic cell,\[\Delta {{G}^{o}}=-nF{{E}^{o}}\] ... (i) Relationship between \[\Delta {{G}^{o}}\] and equilibrium constant \[\Delta {{G}^{o}}=-2.303\,\,RT\,\log \,{{K}_{p}}\] ... (ii) From Eqs. (i) and (ii), we get \[-2.303\,\,RT\,\log \,{{K}_{p}}=-nF{{E}^{o}}\] \[\log \,{{K}_{p}}=\frac{nF{{E}^{o}}}{2.303\,RT}=\frac{n{{E}^{o}}}{\frac{2.303\,RT}{F}}\] \[=\frac{2\times 0.59}{0.059}=20\] \[{{K}_{p}}=AL\,(20)\] (AL = Antilog) \[{{K}_{p}}={{10}^{20}}\]You need to login to perform this action.
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