A) 106 W
B) 150 W
C) 5625 W
D) zero
Correct Answer: C
Solution :
Given \[V=150\sin \,(150\,t)\] volt \[I=150\sin \,(150\,t+\pi /3)\] amp \[\therefore \] \[{{I}_{0}}=150\]volt and \[{{V}_{0}}=150\] volt \[P=\frac{1}{2}\,{{V}_{0}}{{I}_{0}}\cos \phi \] \[P=0.5\times 150\times 150\times \cos {{60}^{o}}\] \[P=5625\,W\]You need to login to perform this action.
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