A) \[hc\left( {{\lambda }_{0}}<\lambda \right)\]
B) \[\frac{hc}{{{\lambda }_{0}}-\lambda }\]
C) \[\frac{h}{c}\left( \frac{{{\lambda }_{0}}-\lambda }{\lambda {{\lambda }_{0}}} \right)\]
D) \[hc\left( \frac{{{\lambda }_{0}}-\lambda }{\lambda {{\lambda }_{0}}} \right)\]
Correct Answer: D
Solution :
\[E=W+K\,E\] \[=\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{0}}}\] \[=hc\left[ \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right]=hc\left[ \frac{{{\lambda }_{0}}-\lambda }{\lambda \,{{\lambda }_{0}}} \right]\]You need to login to perform this action.
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