A) \[{{i}_{1}}=1.5A,{{i}_{2}}=0.5A\]
B) \[{{i}_{1}}=0.5A,{{i}_{2}}=1.5A\]
C) \[{{i}_{1}}=1A,{{i}_{2}}=3A\]
D) \[{{i}_{1}}=3A,{{i}_{2}}=1A\]
Correct Answer: B
Solution :
Resistance \[R=\frac{12\times 4}{12+4}+2=\frac{48}{16}+2=5\,\,\Omega \] Electric current \[I=\frac{E}{R+r}=\frac{12}{6}=2\,A\] \[{{I}_{1}}+{{I}_{2}}=2\,A\] \[I\propto \frac{1}{R}\] \[\therefore \] \[{{I}_{2}}=1.5\,A,\,{{I}_{1}}=0.5\,A\]You need to login to perform this action.
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