CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    The equation of progressive wave is: \[y=0.2\,\sin \,2\pi \left[ \frac{t}{0.01}-\frac{x}{0.3} \right]\] where x and y are in metre and t is in second. The velocity of propagation of the wave is:

    A)  30 m/s

    B)  40 m/s

    C)   300 m/s

    D)  400 m/s

    Correct Answer: A

    Solution :

     Equation of the wave given \[y=0.02\sin 2\pi \left[ \frac{t}{0.01}-\frac{x}{0.3} \right]\] ...(1) The   standard   equation   of   the progressive wave is \[y=0.02\sin 2\pi \left[ \frac{t}{T}-\frac{x}{\lambda } \right]\]   ...(2) Comparing the given equation with the   standard   equation   of   the progressive wave, we get time period, T = 0-01 sec. wavelength, \[\lambda =0.3\] The frequency of the wave is given by \[v=\frac{1}{T}=\frac{1}{0.01}=100Hz.\] Hence, the velocity of propagation of the wave \[\upsilon =v\lambda =100\times 0.3=30m/s\]


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