A) 28 N
B) 14 N
C) 50 N
D) 38 N
Correct Answer: A
Solution :
Force required to separate the plates \[F=\frac{2TA}{a}\] Given : area, \[A={{10}^{-2}}{{m}^{2}}\]thickness \[d=0.05mm=0.05\times {{10}^{-3}}m\] So, \[F=\frac{2\times 10\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}\]\[=28N\]You need to login to perform this action.
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