A) \[+914kJ\]
B) \[+97kJ\]
C) \[-97kJ\]
D) \[-194\text{ }kJ\]
Correct Answer: B
Solution :
\[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl,\Delta H=194kJ\] \[\therefore \] Heat of formation of \[HCl\] \[=\frac{194}{2}=97kJ\]You need to login to perform this action.
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