A) \[1/4\]
B) \[1/2\]
C) \[4\]
D) \[2\]
Correct Answer: C
Solution :
\[A+B\rightleftharpoons C+D\] Initital \[\because \] \[A=B\] At equilibrium \[C=2A\] \[\therefore \] Equilibrium constant \[K=\frac{2A.2A}{A.A}=4\]You need to login to perform this action.
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