A) \[Hg{{I}^{2-}}\]
B) \[HgI_{4}^{2-}\]
C) \[H{{g}^{+}}\]
D) \[H{{g}^{++}}\]
Correct Answer: B
Solution :
Nesslers reagent is \[{{K}_{2}}Hg{{I}_{4}}\]. The ion present is \[HgI_{4}^{2-}\].You need to login to perform this action.
You will be redirected in
3 sec