A) \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{2+}}\]
B) \[{{[Fe(NO)\,\,{{(CN)}_{5}}]}^{2+}}\]
C) \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]
D) \[{{[Fe{{({{H}_{2}}O)}_{5}}{{(NO)}_{5}}]}^{2+}}\]
Correct Answer: C
Solution :
The brown ring test for \[NO_{2}^{-}\] and \[NO_{3}^{-}\] is due to formation of \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]You need to login to perform this action.
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