A) \[0.5Y{{X}^{2}}\]
B) \[0.5{{Y}^{2}}X\]
C) \[2Y{{X}^{2}}\]
D) \[Y{{X}^{2}}\]
Correct Answer: A
Solution :
Given : Youngs modulus = Y Longitudinal strain =X The potential energy stored is given by \[=\frac{1}{2}\times stress\times strain\] \[=\frac{1}{2}\times Y\times X\times X\] \[=\frac{1}{2}Y\,{{X}^{2}}\](\[\because \]stress \[=Y\times \]strain) \[=0.5Y{{X}^{2}}\]
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