A) \[\frac{2q}{{{b}^{2}}}\]
B) \[\frac{q}{2{{b}^{2}}}\]
C) zero
D) \[\frac{q}{{{b}^{2}}}\]
Correct Answer: C
Solution :
The electric field at the centre of the cube due to charges at its vertices is zero.You need to login to perform this action.
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