A) \[{{10}^{7}}\]volt
B) \[{{10}^{6}}\] volt
C) \[{{10}^{5}}\]volt
D) \[{{10}^{4}}\] volt
Correct Answer: C
Solution :
Charge, \[Q=100\mu C=100\times {{10}^{-6}}C={{10}^{-4}}C\] Distance, d = 9 m (given) The relation for the potential is given by \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{Q}{d}=9\times {{10}^{9}}\times \frac{{{10}^{-4}}}{9}\]\[={{10}^{5}}\]volt
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