A) four times the initial value
B) three times the initial value
C) twice the initial value
D) same as the initial value
Correct Answer: C
Solution :
Given : Initial kinetic energy of the body \[{{E}_{1}}=E\] Initial kinetic energy of the body\[{{E}_{2}}=4E\] The kinetic energy of the body is \[=\frac{1}{2}m{{\upsilon }^{2}}\] As m remains constant, hence for the kinetic energy to be four times the new value of velocity v must be two times that of the initial value. The initial linear momentum is \[{{p}_{1}}=m\upsilon \] Hence, the new linear momentum is given by \[{{p}_{2}}=m2\upsilon =2m\upsilon \] \[{{p}_{2}}=2{{p}_{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
