A) \[16.95\times {{10}^{-9}}N\]
B) \[1.695\times {{10}^{-9}}N\]
C) \[10.17\times {{10}^{-9}}N\]
D) \[101.73\times {{10}^{-9}}N\]
Correct Answer: D
Solution :
The formula for viscous force is \[F=6\pi \,\eta \,r\,\upsilon \] Given : Here, viscosity \[\,\eta =18\times {{10}^{-5}}poise=18\times {{10}^{-6}}kg/m\sec \] \[Radiusr=0.3mm=0.3\times {{10}^{-3}}m\] Velocity \[\upsilon =1\text{ }m/s\] So, \[F=6\times 3.14\times 18\times {{10}^{-6}}\times 0.3\times {{10}^{-3}}\times 1\] \[=101.73\times {{10}^{-9}}N\]You need to login to perform this action.
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