A) 100 K, 80 K
B) 80 K, 60 K
C) 60 K, 40 K
D) 40 K, 20 K
Correct Answer: D
Solution :
The efficiency of Carnots engine is \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] The value of efficiency will be higher if \[{{T}_{1}}-{{T}_{2}}\] is more. As \[{{T}_{1}}-{{T}_{2}}\]is constant in all four cases. Therefore, efficiency will be highest when \[{{T}_{1}}\] is the lowest. Therefore, option will be correct.
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