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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    When 9-65 coulombs of electricity is passed through a solution of silver nitrate (atomic mass  of \[Ag=108g\text{ }mo{{l}^{-1}}\]), the amount of silver deposited is:

    A)  \[16-2mg\]       

    B)  \[21-2mg\]

    C)  \[10-8mg\]    

    D)  \[64mg\]

    Correct Answer: C

    Solution :

    Electricity passed \[=9.65\]coulombs The amount of silver deposited =? We know that 96,500 coulombs \[=108\text{ }mo{{l}^{-1}}\] \[\therefore \] 9.65 coulombs \[=\frac{9.65}{96500}\times 108\times {{10}^{-4}}gm=10.8mg\]


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