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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    \[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl,\,\Delta H=194kJ\]. In this reaction heat of formation of \[HCl\] in kJ is:

    A)  \[+914kJ\]       

    B)  \[+97kJ\]

    C)  \[-97kJ\]        

    D)  \[-194\text{ }kJ\]

    Correct Answer: B

    Solution :

    \[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl,\Delta H=194kJ\] \[\therefore \] Heat of formation of \[HCl\] \[=\frac{194}{2}=97kJ\]


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