A) \[5\]
B) \[6\]
C) \[3\]
D) \[4\]
Correct Answer: A
Solution :
The electronic configuration of \[_{26}Fe=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{d}^{6}}4{{s}^{2}}\] \[F{{e}^{+3}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}\] Therefore, the number of unpaired electrons =5
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