CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    On heating ethanol with excess of cone. \[{{H}_{2}}S{{O}_{4}}\] at\[{{170}^{o}}C\], the product obtained is:

    A)  ethene       

    B)  ethoxy ethane

    C)  ethyne      

    D)  ethane

    Correct Answer: A

    Solution :

    \[\underset{Ethanol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[{{170}^{o}}C]{Con.\,{{H}_{2}}S{{O}_{4}}}\underset{\begin{smallmatrix}  Ethylene \\  (Ethene) \end{smallmatrix}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]


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