A) 965 Coulombs
B) 1 Faraday
C) 0.1 Faraday
D) 96500 Coulombs
Correct Answer: A
Solution :
We know that 96,500 coulombs \[=11,200c{{m}^{3}}\]of \[{{H}_{2}}\] \[\therefore \] \[112\,c{{m}^{2}}\] of \[{{H}_{2}}=\frac{96500\times 112}{11200}\] = 965 coulombs
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