A) zero
B) \[\frac{1}{2}\]PV
C) PV
D) 2PV
Correct Answer: C
Solution :
The work done during the process from P to Q= area PQRSTP (positive sign is to be taken due to expansion along PQ) Area of triangle PQR + area of rectangle PRST \[=\frac{1}{2}\times 2\times 1\times 1\times 2=3PV\] Work done during process from R to P = - Area RSTP (negative sign due to compression in atom RP)\[=-ST\times PT=-2\times 1=-2PV\] Hence, the work done in the complete cycle \[=3PV-2PV=PV\]
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