A) \[4\]
B) \[2\]
C) \[1/4\]
D) \[1/2\]
Correct Answer: A
Solution :
Conversion of \[A\xrightarrow{{}}B\] follows second order kinetics therefore, \[r=K{{[A]}^{2}}\] The concentration is doubled \[r=K{{[2A]}^{2}}=K4{{[A]}^{2}}\] Therefore, the new rate becomes four times.You need to login to perform this action.
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