A) \[{{K}_{c}}={{(RT)}^{2}}\]
B) \[{{K}_{c}}(RT)\]
C) \[\frac{{{K}_{c}}}{{{(RT)}^{2}}}\]
D) \[{{K}_{c}}\]
Correct Answer: A
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] We know that \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] Hence \[\Delta n=2-4=-2\] Hence \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-2}}=\frac{{{K}_{c}}}{{{(RT)}^{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec