A) \[\Delta H>T\Delta S\]
B) \[\Delta H=T\Delta S\]
C) \[\Delta H=\Delta G\]
D) \[\Delta H<T\Delta S\]
Correct Answer: B
Solution :
\[{{H}_{2}}O(g)\rightleftharpoons {{H}_{2}}O(l)\] We know that \[\Delta G=\Delta H-T\Delta S\] At equilibrium \[\Delta G=0\] Therefore \[\Delta H=T\Delta S\]You need to login to perform this action.
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