A) \[0\]
B) \[12.5\]
C) \[8\]
D) \[25\]
Correct Answer: D
Solution :
We know that \[{{C}_{n}}=\frac{C}{{{2}^{n}}}\] \[{{C}_{n}}=\] concentration after n half-lives n = number of half-lives \[C=\] initial concentration \[{{C}_{n}}=\frac{1}{{{2}^{2}}}=\frac{1}{4}=0.25\] or \[25%\]
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