CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    The  oxidation  number  and  the electronic configuration of sulphur in \[{{H}_{2}}S{{O}_{4}}\] is:

    A)  \[+4;1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}\]

    B)  \[+2;1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{2}}\]

    C)  \[+3;1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{1}}\]

    D)  \[+6;1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}\]

    Correct Answer: D

    Solution :

    The oxidation number of sulphur in \[{{H}_{2}}S{{O}_{4}}\] is \[(2\times 1)+x+(4\times -2)=0\] \[\therefore \] \[2+x+(-8)=0\] \[\therefore \] \[x=8-2=+6\] The electronic configuration of sulphur \[_{16}S=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{4}}\] Electronic configuration of S in \[{{H}_{2}}S{{O}_{4}}\] \[16-6=10,\]  \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}\]


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