2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2002

  • question_answer
    The load versus elongation graph for four wires of the same materials is shown in the figure. The thinnest Wire is elongation represented by the line:

    A)  OC

    B)  OD

    C)  OA

    D)  OB

    Correct Answer: C

    Solution :

     Stress\[\propto \]strain \[\frac{F}{A}=Y\frac{\Delta l}{l}\] \[\Delta l=\] F = load Y= Youngs modulus A = area l = length of wire \[F\propto {{r}^{2}}\] (radius of wire). \[\Delta l\propto \frac{1}{{{r}^{2}}}\] \[\therefore \]Thin wire max. elongation with min load. Graph is OA.


You need to login to perform this action.
You will be redirected in 3 sec spinner