CET Karnataka Medical
CET - Karnataka Medical Solved Paper-2002
question_answer
A ray of light travels from an optically denser to a rarer medium. The critical angle for the two media is C. The maximum possible deviation of the ray will be:
A) 2C
B) \[\frac{\pi }{2}-C\]
C) \[\pi \]-C
D) \[\pi -2C\]
Correct Answer:
B
Solution :
OA = incident ray \[\Delta S=\] interface which separates the two medium. OB = actual path of the incident ray. \[\angle C=\]critical angle. \[\angle QOB\]is also \[=\angle C\] After incidence ray refract towards OS. \[\therefore \]Deviation \[(\delta )=\angle BOS\] \[=\frac{\pi }{2}-C\]