A) 1.68 V, 0.47 A
B) 0 V, 0.47 A
C) 5.6 V, 1.4 A
D) 0V, 1.4 A
Correct Answer: C
Solution :
\[Z=\sqrt{{{10}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[{{X}_{L}}=2000\times {{510}^{-3}}=10\Omega \] \[{{X}_{C}}=\frac{1}{WC}=\frac{1}{200\times 50\times {{10}^{-6}}}=10\Omega \] \[Z=\sqrt{{{10}^{2}}+0}=10\Omega \] Reading of ammeter \[=\frac{V}{R}=\frac{20}{10}\]\[{{i}_{\max }}=2amp.\] \[{{i}_{r.m.s.}}=\frac{2}{\sqrt{2}}=1.41amp.\] \[{{V}_{r.m.s.}}=4\times 1.41=5.64V\]
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