A) OC
B) OD
C) OA
D) OB
Correct Answer: C
Solution :
Stress\[\propto \]strain \[\frac{F}{A}=Y\frac{\Delta l}{l}\] \[\Delta l=\] F = load Y= Youngs modulus A = area l = length of wire \[F\propto {{r}^{2}}\] (radius of wire). \[\Delta l\propto \frac{1}{{{r}^{2}}}\] \[\therefore \]Thin wire max. elongation with min load. Graph is OA.You need to login to perform this action.
You will be redirected in
3 sec