A) 1 : 173
B) 1.73 : 1
C) 1 : 2
D) 1 : 1
Correct Answer: A
Solution :
\[{{T}_{1}}=200+273={{473}^{o}}K\] \[{{T}_{2}}=0+273={{273}^{o}}K\] \[{{\mu }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}=42.2%\] For second \[{{T}_{1}}=0+273={{273}^{o}}K\] \[{{T}_{2}}=-200+273={{73}^{o}}K\] \[{{\mu }_{2}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\]\[=73.2%\] \[\frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{42.2}{73.2}=\frac{1}{1.73}\] \[{{\mu }_{1}}:{{\mu }_{2}}=1:1.73\]You need to login to perform this action.
You will be redirected in
3 sec