A) \[\frac{{{\mu }_{0}}I}{2}\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\]
B) \[\frac{{{\mu }_{0}}I}{4}\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\]
C) \[\frac{{{\mu }_{0}}I}{2}\left( \frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \right)\]
D) \[\frac{{{\mu }_{0}}I}{4}\left( \frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \right)\]
Correct Answer: B
Solution :
Magnetic field at C due to AB and DE = zero Magnetic field due to semicircular arc \[BPD=\frac{{{\mu }_{0}}I}{4\pi {{R}_{2}}}\](downward) Magnetic field due to semicircular arc (upward) \[{{B}_{net}}=\left( \frac{{{\mu }_{0}}I}{4{{R}_{1}}}-\frac{{{\mu }_{0}}I}{4{{R}_{2}}} \right)\](upward)You need to login to perform this action.
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