A) 210
B) 400
C) 205
D) 200
Correct Answer: D
Solution :
\[{{f}_{1}}=\] frequency of first fork. \[{{f}_{41}}=\] frequency of 41st fork. \[{{f}_{41}}=2{{f}_{1}}\] Between Ist and 41st there are 40 intervals each interval produces 5 beats. \[{{f}_{41}}-{{f}_{1}}=40\times 5\] \[2{{f}_{1}}-{{f}_{1}}=200\] \[{{f}_{1}}=200Hz\]You need to login to perform this action.
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