A) 280 Hz
B) 360 Hz
C) 56 Hz
D) 560 Hz
Correct Answer: C
Solution :
\[f=\frac{n}{T}=\frac{8}{T}\]velocity attain by plate to fall 10 cm. \[\upsilon =\sqrt{2gh}\] \[=\sqrt{2\times 10\times 0.1}\] \[=\sqrt{2}cm/\sec .\] Time taken to reach 10 cm. \[\upsilon =u+gt\] \[\sqrt{2}=10t\Rightarrow t=\frac{\sqrt{2}}{10}\sec \] \[f=\frac{8\times 10}{\sqrt{2}}=56.73Hz.\]You need to login to perform this action.
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