A) 75%
B) 100%
C) 25%
D) 50%
Correct Answer: C
Solution :
Energy stored in a capacitor\[=\frac{1}{2}qV.\]Where \[qV=\] total energy of battery \[\therefore \] \[{{E}_{c}}=\frac{{{E}_{b}}}{2}=50%\]You need to login to perform this action.
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