CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    A bucket full of hot water is kept in a room. It cools from \[75{}^\circ C\] to \[70{}^\circ C\] in \[{{t}_{1}}\]minutes, from \[70{}^\circ C\] to \[65{}^\circ C\] in \[{{t}_{2}}\]minutes and from \[65{}^\circ C\]to \[60{}^\circ C\]in 13 minutes. Then:

    A)  \[{{t}_{1}}<{{t}_{2}}<{{t}_{3}}\]

    B)  \[{{t}_{1}}={{t}_{2}}={{t}_{3}}\]

    C)  \[{{t}_{1}}<{{t}_{2}}>{{t}_{3}}\]

    D)  \[{{t}_{1}}>{{t}_{2}}>{{t}_{3}}\]

    Correct Answer: A

    Solution :

    According to Newtons law of cooling we have, rate of cooling \[\propto \] temperature difference between the liquid and surrounding. As temperature difference decreases gradually, time taken to cool increases i.e.,   \[{{T}_{1}}<{{T}_{2}}<{{T}_{3}}\]


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