A) \[p\]
B) \[s\]
C) \[f\]
D) \[d\]
Correct Answer: A
Solution :
Electronic configuration of element with atomic number 36, will be \[=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},4{{s}^{2}}4ph6\] As the last electron is present in p-subshell, hence the element will be placed in p-block.
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