A) \[224c{{m}^{3}}\]
B) \[1.008g\]
C) \[112c{{m}^{3}}\]
D) \[22400c{{m}^{3}}\]
Correct Answer: C
Solution :
According to Faradays second law of electrolysis, we have \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] \[\therefore \] \[\frac{1.08}{x}=\frac{108}{1}\] \[\therefore \]weight of hydrogen \[\text{(x)}=0.01\text{ }g\] Hence, the volume of hydrogen at \[STP=\frac{22400\times 0.01}{2}=112c{{m}^{3}}\]You need to login to perform this action.
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