A) \[4,2\]
B) \[2,2\]
C) \[8,6\]
D) \[6,4\]
Correct Answer: D
Solution :
No. of a-particles \[=\frac{1}{4}\times \] (Difference in mass number) \[=\frac{1}{4}\times (232-208)=\frac{1}{4}\times 24=6\] No. of \[\beta \]-particles \[=2\times \alpha \]-particles (Difference in atomic number) \[=2\times 6-(90-82)=12-8=4\]You need to login to perform this action.
You will be redirected in
3 sec