A) \[\frac{nh}{2\pi }\]
B) \[nh\]
C) \[\frac{2\pi }{nh}\]
D) \[\frac{\pi }{2nh}\]
Correct Answer: A
Solution :
According to Bohr, an electron can move only in those orbits in which its angular momentum is a simple multiple of \[\frac{h}{2\pi }\]. i.e., equal to \[\frac{nh}{2\pi }\] (where n, is an integer)You need to login to perform this action.
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