A) 40 V
B) -40 V
C) 300 V
D) 140 V
Correct Answer: A
Solution :
The induced e.m.f \[e=-\frac{d\phi }{dt}\] So, \[e=-\frac{d}{dt}(5{{t}^{3}}-100t+300)\] or \[e=-(15{{t}^{2}}-100)\] Induced e.m.f at t = 2 sec \[e=-(15\times 4-100)=+40volt\]You need to login to perform this action.
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