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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    The magnetic flux linked with a coil at any instant   t is given by \[\phi =5{{t}^{3}}-100t+300,\]the emf induced in the coil at t = 2 second is:

    A)  40 V

    B)  -40 V

    C)  300 V

    D)  140 V

    Correct Answer: A

    Solution :

    The induced e.m.f  \[e=-\frac{d\phi }{dt}\] So,  \[e=-\frac{d}{dt}(5{{t}^{3}}-100t+300)\] or   \[e=-(15{{t}^{2}}-100)\] Induced e.m.f at t = 2 sec \[e=-(15\times 4-100)=+40volt\]


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