2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    The time taken by A.C. of 50 Hz in reaching from zero to the maximum value is:

    A) \[50\times {{10}^{-3}}sec\]

    B)  \[5\times {{10}^{-3}}sec\]

    C) \[1\times {{10}^{-3}}sec\]

    D)  \[2\times {{10}^{-3}}sec\]

    Correct Answer: B

    Solution :

    The time taken by a.c in reaching from zero to maximum value is \[t=\frac{T}{4}=\frac{1}{4f}=\frac{1}{50\times 4}\] \[5\times {{10}^{-3}}\sec \]


You need to login to perform this action.
You will be redirected in 3 sec spinner