A) \[\overrightarrow{C}\]
B) \[\overrightarrow{B}\]
C) \[\overrightarrow{B}\times \overrightarrow{C}\]
D) \[\overrightarrow{B}.\overrightarrow{C}\]
Correct Answer: C
Solution :
Since, \[\overrightarrow{A}.\overrightarrow{B}=0\] \[\Rightarrow \] \[\overrightarrow{A}\bot \overrightarrow{B}\] \[\overrightarrow{A}.\overrightarrow{C}=0\] \[\Rightarrow \] \[\overrightarrow{A}\bot \overrightarrow{C}\] \[\Rightarrow \] \[\overrightarrow{A}\bot \overrightarrow{B}\] and \[\overrightarrow{A}\bot \overrightarrow{C}\] Since, the direction of \[\overrightarrow{B}\bot \overrightarrow{C}\] is \[\bot \] to \[\overrightarrow{B}\] and \[\overrightarrow{C}\] both i.e., parallel to \[\overrightarrow{A}\].You need to login to perform this action.
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