A) + Q / 4
B) - Q / 2
C) + Q / 2
D) - Q / 4
Correct Answer: D
Solution :
For equilibrium of system of charges force produced between q and Q+ force produced between Q and Q = 0 \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{qQ}{{{(r/2)}^{2}}}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{QQ}{{{r}^{2}}}=0\] \[\Rightarrow \] \[\frac{4qQ}{{{r}^{2}}}+\frac{QQ}{{{r}^{2}}}=0\] \[\Rightarrow \] \[q=-\frac{Q}{4}\]You need to login to perform this action.
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