A) \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]
B) \[ZnS{{O}_{4}}\]
C) \[MgS{{O}_{4}}\]
D) \[SnC{{l}_{2}}\]
Correct Answer: C
Solution :
This salt is \[MgS{{O}_{4}}\]. It is soluble in dilute \[HCl\] With \[NaOH\], it gives white precipitate of magnesium hydroxide, which is insoluble in excess of \[NaOH\]. \[MgS{{O}_{4}}+2HCl\xrightarrow{{}}MgC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\] \[MgS{{O}_{4}}+2NaOH\xrightarrow{{}}Mg{{(OH)}_{2}}\downarrow +N{{a}_{2}}S{{O}_{4}}\]\[Mg{{(OH)}_{2}}+NaOH\xrightarrow{{}}\times (No\,reaction)\] While other hydroxides form -soluble salts, \[NaAl{{O}_{2}}\], \[N{{a}_{2}}Zn{{O}_{2}}\]and \[N{{a}_{2}}Sn{{O}_{2}}\] respectively.
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