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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    Same amount of electric current is passed through solutions of \[AgN{{O}_{3}}\] and \[HCl\], If 1.08 g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is:

    A)  \[224c{{m}^{3}}\]      

    B)  \[1.008g\]

    C)   \[112c{{m}^{3}}\]     

    D)  \[22400c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    According to Faradays second law of electrolysis, we have \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] \[\therefore \] \[\frac{1.08}{x}=\frac{108}{1}\] \[\therefore \]weight of hydrogen \[\text{(x)}=0.01\text{ }g\] Hence, the volume of hydrogen at \[STP=\frac{22400\times 0.01}{2}=112c{{m}^{3}}\]


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