A) \[5.02\times {{10}^{23}}\]
B) \[5.02\times {{10}^{20}}\]
C) \[6.02\times {{10}^{20}}\]
D) \[0.502\times {{10}^{20}}\]
Correct Answer: D
Solution :
Number of atoms present in 12 g carbon \[=6.023\times {{10}^{23}}\] \[\therefore \]No. of atoms present in 1 mg carbon \[=\frac{6.023\times {{10}^{23}}\times 1}{12\times 1000}\] \[=0.502\times {{10}^{20}}\]
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