A) P/2
B) P/4
C) P
D) 2P
Correct Answer: C
Solution :
The resultant force of two equal forces \[=\sqrt{{{P}^{2}}+{{P}^{2}}+2P.P\cos {{120}^{o}}}\] \[=\sqrt{2{{P}^{2}}+2{{P}^{2}}\times \left( -\frac{1}{2} \right)}\] \[=\sqrt{2{{P}^{2}}-{{P}^{2}}}=\sqrt{{{P}^{2}}}=P\]You need to login to perform this action.
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